According to the degree of unsaturation formula, C3H8O2 has no double bonds or rings.
We are also obeying the normal rules of valence, (and this chart) there will be:
Here are 8 isomers I could think of. Can you find more?
According to the degree of unsaturation formula, the formula C4H8 has 1 double bond or ring.
The problem states that there cannot be any rings (non-cyclic constitutional isomers), so we know there must be 1 double bond in this 4-carbon molecule.
Here are the bond-line formulas of the 4 non-cyclic constitutional isomers of C4H8:
Saturation can me many things. In organic chemistry, a molecule is saturated when it has the maximum number of hydrogens attached.
A molecule becomes unsaturated due to double bonds, triple bonds, and rings.
Given a molecular formula, you can calculate the degrees of unsaturation:
Each double bond or ring increases the molecule’s degree of unsaturation by 1. A triple bond increases the degree of unsaturation by 2.
